A system consisting of an ideal gas at the constant pressure of 119 kPa gains 92

Question

A system consisting of an ideal gas at the constant pressure of 119 kPa gains 920 J of heat.
(a) Find the change in volume of the system if the internal energy of the gas increases by 920 J.
m3
(b) Find the change in volume if the internal energy increases by 380 J.
m3
7. –/3 points Notes Question: Walker3 18.P.014.
Consider a system in which 5.00 mol of an ideal monatomic gas is expanded at a constant pressure of 101 kPa from an initial volume of 2.15 L to a final volume of 3.53 L.
(a) Is heat added to or removed from the system during this process?
?removed
?added
?no change in heat

Explain.

(b) Find the change in temperature for this process.
——————K
(c) Determine the amount of heat added to or removed from the system during this process.
——————J

Explanation / Answer

given that number moles n = 5 intial volume v1 = 2.15L final volume v2 = 3.53L preesure P = 101kpa (a) the expansion of the gas constant pressure implies that work was done by the gas . heat is required gas to do work therefore heat was added to teh system. b) v1/T1 = v2/T2 T2 =( v2/v1) T1 from teh ideal gas eq pv= nRT T1 = pv1/nR    T = T2- T1      plugging above values     = (v2/v1 -1) T1    = (v2/v1 -1)pv1/nR     = ( v2-v1) p/nR     = (3.53L -2.15L) * 1.01 * 105pa/ 5 * 8.31J/mol.k     = 3354.5K c)Q= U+W            = 3/2) nRT +pV            = ( 3/2) 5 ( 8.31 J/mol.k) 3354.5 J + 1.01 * 105 pa ( 3.53 L- 2.15L            = 348449.2J from the cramster rules only one post be answered please post next question second time   I will answer you thank u    = (v2/v1 -1)pv1/nR     = ( v2-v1) p/nR     = (3.53L -2.15L) * 1.01 * 105pa/ 5 * 8.31J/mol.k     = 3354.5K c)Q= U+W            = 3/2) nRT +pV            = ( 3/2) 5 ( 8.31 J/mol.k) 3354.5 J + 1.01 * 105 pa ( 3.53 L- 2.15L            = 348449.2J from the cramster rules only one post be answered please post next question second time   I will answer you thank u

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