19. Making n-fold dilutions: One part of a stock solution is added into 4 parts

Question

19. Making n-fold dilutions: One part of a stock solution is added into 4 parts of a diluent. What is the fold dilution here? (2 points) ) How many parts of the diluent is does an 8-fold solution contains if one part of the original stock solution is added? (2 points) b) 20, Craig made serial dilutions from, his stock solution (A). Craig placed 50 of the original stock solution into tube B containing 450 L of the diluent. Each consecutive tube also contained 450 L of the diluent. Craig made a total of four serial dilutions. a) What is the dilution factor? Show your work. (2 points) b) What dilution is tube "C" to tube "A"? (2 points) c) What dilution is tube "D" to tube "C"? (2 points) 21. Jane added 10 gram of LB broth to 1 liter of deionized water a) What is the concentration of the LB solution? Show your work (5 points) b) Convert the concentration to a percent solution. Show your work (5 points) c) How much water is needed to generate 0.5 g/ml. of a KCI solution if 20 g of k Cl is used? Show your work (5 points)

Explanation / Answer

19.

a.

1 part stock + 4 parts diluent

Fold dilution = 1/5 = 0.2

= 5 fold dilution

b.

For an 8-fold dilution, we need to take 1 mL stock and mix it with 7 mL diluent.

20.

A = stock

B = Dilution 1 = 50 + 450 = 10 fold dilution

C = Dilution 2 = 50 mL dilution 1 + 450 uL = 10 X 10 = 100 fold dilution

D = Dilution 3 = 50 mL dilution 2 + 450 uL = 10 X 10 X 10 = 1000 fold dilution

21.

a. Concentration of LB = 10 g/L = 1 g/100 mL = 0.01 g/mL = 10 mg/mL

b. Concentration = 1 g/100 mL = 1% solution

c.

=0.5 g/mL

= 500 g/L

= 1 kg/2L

= 20 kg/40 L

So, 40L of water is required.

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