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Question

<p><img src="https://s3.amazonaws.com/answer-board-image/f6ed729d-9a26-411a-8474-5e0e512807c8.jpg" alt="image from custom entry tool" />The drawing shows a jet engine suspended beneath the wing of an airplane. The weight W of the engine is 11800 N and acts as shown in the drawing. In flight the engine produces a thrust T of 58400 N that is parallel to the ground. The rotational axis in the drawing is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to each of the following forces. <br /><br /><br />(a) the weight <br />____ N&#183;m<br /><br />(b) the thrust <br />____ N&#183;m<br /><br />can you show me how to work this problem and give me the correct answers</p>

Explanation / Answer

Given that Weight of the engine is W = 11800 N thrust T = 58400 N The magnitude of the torque due to the weight is     = Wl sin         = (11800 N)(2.5 m)sin32          = 15632.618 N.m The magnitude of the torque due to thrust is              =  Wl sin                 = ( 58400 N)(2.5 m)sin(90-32)                 = 123815.022 N.m The magnitude of the torque due to thrust is              =  Wl sin                 = ( 58400 N)(2.5 m)sin(90-32)                 = 123815.022 N.m

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