The charging curve for a capacitor connected in series with a resistor is shown

Question

 

 

 

The charging curve for a capacitor connected in series with a resistor is shown below.

a) If you wait long enough, what do you expect the potential difference across the resistor to be?

b) if the capacitance of the capacitor is 3.3 microfarads, what is the resistance of the resistor?

c) after the capacitor is charged, it is discharged through a resistor with a value 1/2 that of what you found in part b). How much time after discharging begins is required for the potential difference across the capacitor to reach 10 volts?

t is in seconds and VC is in volts.

possible equations you can use:

C= Q/V

Potential difference across the capacitor during charging : Vc = Vo (1-e^(-t/RC))

Potential difference across the capacitor during discharging: Vc = Vo* e^(-t/RC)

 

Please help me answer this question asap.

The charging curve for a capacitor connected in series with a resistor is shown below. a) If you wait long enough, what do you expect the potential difference across the resistor to be? b) if the capacitance of the capacitor is 3.3 microfarads, what is the resistance of the resistor? c) after the capacitor is charged, it is discharged through a resistor with a value 1/2 that of what you found in part b). How much time after discharging begins is required for the potential difference across the capacitor to reach 10 volts? t is in seconds and VC is in volts. possible equations you can use: C= Q/V Potential difference across the capacitor during charging : Vc = Vo (1-e^(-t/RC)) Potential difference across the capacitor during discharging: Vc = Vo* e^(-t/RC) Please help me answer this question asap.

Explanation / Answer

a) 0 b) Vc = Vo (1-e^(-t/RC)) t = 10 VC = 17.5 C = 3.3 x 10^3 F Vo = 20 answer: R = 1.46 x 10^3 ohms c) t=1.67s ln(10/20) * 0.0033 F * (1.46x10^3)/2 = 1.67

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