The charge earned by one electron is e = -1 6 Times 10^-19 C the number of elect

Question

The charge earned by one electron is e = -1 6 Times 10^-19 C the number of electrons necessary to produce a charge of -1.0 C is 6-3 Times 10^18. 1.6 Times 10^9 6.3 Times 10^9. 1.6. Times 10^19. none of the above The force of attraction between a -40.0 mu C and + 108 mu C charge is 4.00 N What is the separation between these two charges? 1.13 m 2.10 m 3.12 m 2.49 m 3.67 m An atomic nucleus has a charge of +40e An electron is 10-9 m from the nucleus. What is the force on the electron? 2.9 nN 9.2 nN 3.7 nN 1000 C 6 8 nN A force of 10 N acts on a charge of 5.0 mu C when it is placed in a uniform electric field What is the magnitude of this electric field? 1.0 MN/C 50MN/C 0.50 MN/C 1000 MN/C 2.0 MN/C Fig. 15-8 shows electric field lines near two electric point charges. If Q_1 = -1 mu C, what is the value of Q_2? -1 mu C 0 +1 mu C -2 mu + 2 mu C

Explanation / Answer

1)The charge of one electron is given by

            1 e = - 1.6 * 10-19 C

Then – 1 C = 1 e / ( 1.6 * 10-19 )

                  = 6.25 * 1018 e

So one coulomb charge has 6.25 * 1018 electrons

2)Let q1 and q2 be two charges separated by a distance r

Then q1 = - 40 µC = - 40 * 10-6 C

And    q2 = 108 µC = 108 * 10-6 C

Force b/w them is given by F = 4 N

By coulomb’s law

F = 1/40 * ( q1 * q2 / r2)

4 = 9 * 109 * ( 40 * 10-6 * 108 * 10-6 ) / r2

Then r2 = 9 * 109 * 40 * 108 * 10-12 / 4

             = 9.72

     So r = 3.12 m   

3)The charge on the nucleus is q1 = 40 e

Charge of an electron is given by e- = 1.6 * 10-19 C

Distance b/w them is given by r = 10-9 m

Again by coulomb’s law

    F = 1/40 * ( q1 * q2 /r2 )

       = 9 * 109 * 40 * 1.6 * 10-19 * 1.6 * 10-19 / ( 10-9 )2

       = 921.6 * 10-11 N

       = 9.2 nN

4)The force acting on the charge is given by F = 10 N

The charge is given by q = 5 µC

The electric field is given by E = F / q

            So E = 10 / ( 5 * 10-6 )

                    = 2 * 106 N/C

                    = 2 MN/C

5)Electric field lines point outward for a positive charge

From the figure we can easily observe the charge is doubled by the increase in the field lines

So the charge is +2µC

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