A ball whose mass is 0.13 kg has an initial velocity whose horizontal component

Question

A ball whose mass is 0.13 kg has an initial velocity whose horizontal component is 3 m/s and whose vertical component is 2.5 m/s. (Let the potential energy be zero at the starting point. Neglect dissipative forces.)
(a) What is its kinetic energy at the starting point and at the ending point when it returns to the same height?
J.
(b) What is its kinetic energy at the highest point?
J.
(c) What is its potential energy at the highest point?
J.
(d) What is its potential energy at 1/3 of the maximum height?
J.
(e) What is its kinetic energy at 1/3 of the maximum height?
J.
(f) What is the speed of the ball at 1/3 of the maximum height?
m/s.
(g) What is the horizontal component of the ball's velocity at that point?
m/s.
(h) What is the vertical component of the ball's velocity there?
m/s

Explanation / Answer

Here ,

m = 0.13 Kg

vx = 3 m/s

vy = 2.5 m/s

a) at the same height

kinetic energy = 0.5 * 0.13 * (3^2 + 2.5^2)

kinetic energy = 0.9913 J

b)

at the highest point ,
kinetic energy = 0.5 * 0.13 * vx^2
kinetic energy = 0.5 * 0.13 * 3^2

kinetic energy = 0.585 J

c)

potential energy at the highest point = kinetic energy due to vertical velocity

potential energy at the highest point = 0.5 * 0.13 * 2.5^2

potential energy at the highest point = 0.41 J

d)

at 1/3 the maximum height

potential energy is directly proporational to height ,

potential energy will be 1/3 times

potential energy at 1/3 of the maximum height = 0.41/3

potential energy at 1/3 of the maximum height = 0.135 J
======================

please post rest in a seperate post

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.