The figure (Figure 1) shows a portion of a silver ribbon with z 1 = 12.0 mm and

Question

The figure (Figure 1) shows a portion of a silver ribbon with z1 = 12.0 mm and y1 = 0.20 mm , carrying a current of 140 A in the +x-direction. The ribbon lies in a uniform magnetic field, in the y-direction, with magnitude 0.95 T . Apply the simplified model of the Hall effect.

Part A

If there are 5.80×1028 free electrons per cubic meter, find the magnitude of the drift velocity of the electrons in the x-direction.

vd = ______m/s   

Part B

Find the magnitude of the electric field in the z-direction due to the Hall effect.

Express your answer using two significant figures.

E=_________V/m

Part C

Find the direction of the electric field in the z-direction due to the Hall effect.

1- +z

2-  ?z

Part D

Find the Hall emf.

Express your answer using two significant figures.

EHall =___________V

Explanation / Answer

a)

drift velocity, v = I/nAq

So, v = 140/(5.8*10^28*12*0.2*10^-6*1.6*10^-19)

So, v = 6.3*10^-3 m/s

b)

Hall voltage , V = v*B*z1 = 6.3*10^-3*0.95*d

So, Electric field , E = V/z1 = 6.3*10^-3*0.95 = 5.99*10^-3 V/m

c)

direction = +z axis <----- using Fleming's LEft Hand thumb rule

d)

Hall emf = v*B*z1

=  6.3*10^-3*0.95*12*10^-3

= 7.2*10^-5 V

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