The figure ( Figure 1 ) shows a model of a crane that may be mounted on a truck.

Question

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 85.00kg and length L = 5.300m is supported by two vertical massless strings. String A is attached at a distance d = 1.100m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 2500kg is supported by the crane at a distance x = 5.100m from the left end of the bar.

Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity.

I need help finding the tension in string A

and then I need to find the magnitude of the tension in string B

all in Newtons

help would be appreciated!!

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 85.00kg and length L = 5.300m is supported by two vertical massless strings. String A is attached at a distance d = 1.100m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 2500kg is supported by the crane at a distance x = 5.100m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity.

Explanation / Answer

net torque = 0

Ta*d = m1*g*(L/2) + m2*g*x

Ta*1.1 = (85*9.8*(5.3/2)) + (2500*9.8*5.1)

Ta = 115597.682 N
net force = 0

Ta = Tb+m1g+m2g

Tb = 90264.682 N

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