The figure ( Figure 1 ) shows a model of a crane that may be mounted on a truck.

Question

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 75.00kg and length L = 5.800m is supported by two vertical massless strings. String A is attached at a distance d = 1.300m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500kg is supported by the crane at a distance x = 5.600m from the left end of the bar.

Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity.

Find TA, the tension in string A.

Find TB, the magnitude of the tension in string B.

Explanation / Answer

let Ta is upward
Tb is downward
Ta=Tb+75* g+3500*g
moment about B
Ta*1.3-75*9.807*(5.8/2)-3500*9.807 *5.6=0
Ta=149393 N
Tb= 149393 -(75+3500)9.807

Tb =114358 N

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