Suppose your are designing a machine with a component that is a plate loaded in

Question

Suppose your are designing a machine with a component that is a plate loaded in tension. It has a track in one edge (Figure B). The applied force is P = 55 kN. The plate width is b = 40 mm, and the track length is a = 6 mm. The material has high yield strength so you only need to design to avoid failure by brittle fracture. The design code requires a safety factor against fracture of 3.0 At room temperature the material has a fracture toughness K_1c = 66MPa squareroot m. For a component to be used at room temperature, what minimum plate thickness t_room-temp required? Express t_room-temp in unit of mm. In very cold temperature, the toughness of this material will decrease to become K_1C^cold = beta K_1C = beta(66) MPa squareroot m where beta is given by experimental data and is less than 1 For a component to be used at cold temperature, what minimum plate thickness t_cold-temp required? Express t_cold-temp in terms of t_room-temp and beta. Plate with edge crack under Bending Moment M K = FS squareroot pi a S = 6M/tb^2 F_b = 1.12 (a/b lessthanorequalto 0.4) For any alpha = a/b: F = squareroot 2/pi alpha tan pi alpha/2 [0.923 + 0.199(1 - sin pi alpha/2)^4/cos pi alpha/2] Plate with edge crack under Tensile Force F_t = 1.12 (a/b lessthanorequalto 0.13) For any alpha = a/b: F_t = 0.265(1 - alpha)^4 + 0.857 + 0.2/(1 - alpha)^3 Engineer Fred finds that a plate in a machine has developed a crack on an edge. He machine shop to make a replacement part, and the busy machine shop says it will take

Explanation / Answer

Fracture toughness at room temperature is given by,.

K =Fsa

Also,we know that,

S=6m/tb^2,

K = F×6m/tb^2

F = 55KN, =3.14,b =40mm and a =6mm.

All the values are given,we just need to compute the values and find out t.

Therefore,it can be clearly found out.

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