A block of mass 1.34 kg is placed on top of a second block of mass 4.21 kg. The

Question

A block of mass 1.34 kg is placed on top of a
second block of mass 4.21 kg. The coefficient
of kinetic friction between the 4.21 kg block
and the surface is 0.21. A horizontal force F
is applied to the 4.21 kg block.
Calculate the magnitude of the force neces-
sary to pull both blocks to the right with an
acceleration of 3.19 m/s2. Assume no slipping
between the two blocks. The acceleration of
gravity is 9.8 m/s2 .
Answer in units of N   part 2 find the minimum coefficient of static frction between the blocks such that the 1.34 kg block does not slip under the acceleration of 3.19 m/s2   A block of mass 1.34 kg is placed on top of a
second block of mass 4.21 kg. The coefficient
of kinetic friction between the 4.21 kg block
and the surface is 0.21. A horizontal force F
is applied to the 4.21 kg block.
Calculate the magnitude of the force neces-
sary to pull both blocks to the right with an
acceleration of 3.19 m/s2. Assume no slipping
between the two blocks. The acceleration of
gravity is 9.8 m/s2 .
Answer in units of N   part 2 find the minimum coefficient of static frction between the blocks such that the 1.34 kg block does not slip under the acceleration of 3.19 m/s2 find the minimum coefficient of static frction between the blocks such that the 1.34 kg block does not slip under the acceleration of 3.19 m/s2  

Explanation / Answer

a. Ma = F - u(m+M)g 4.21 x 3.19 = F - 0.21 x(4.21 + 1.34) x 9.8 Force = F = 24.8518 Newton b. u = a/g = 3.19/9.8 = 0.3255

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