An 8.9 kg block of metal is suspended from a scale and immersed in water, as in

Question

An 8.9 kg block of metal is suspended from a scale and immersed in water, as in the figure below. The dimensions of the block are 12.0 cm 8.3 cm 8.3 cm. The 12.0 cm dimension is vertical, and the top of the block is 5.00 cm below the surface of the water.

(a) What are the forces exerted by the water on the top and bottom of the block? Take P0 = 1.0130 105 N/m2.
Ftop N
Fbottom N

(b) What is the reading of the spring scale?
N

(c) Show that the buoyant force equals the difference between the forces at the top and bottom of the block. (Do this on paper. Your instructor may ask you to turn in this work.)

Explanation / Answer

(a) Ptop = ?gh + P atm = 1000*9.8*0.05 + 101325 = 101815N/m^2 F top = Pressure*area = 101815*0.083*0.083 = 701.403 N P bottom = 1000*9.8*(0.05+0.12) = 102991N/m^2 Fbottom = 102991*0.083*0.083 = 709.505 N Try this

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