A car is parked on a cliff overlooking the ocean on an incline that makes an ang

Question

A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 20.0° below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 3.21 m/s2 for a distance of 40.0 m to the edge of the cliff, which is 45.0 m above the ocean.
(a) Find the car's position relative to the base of the cliff when the car lands in the ocean.
m

(b) Find the length of time the car is in the air.
s

Explanation / Answer

so for the car we can write v^2=u^2+2as where u=0, a=3.21 and s=40. so v=Sqrt(2*2.9*65)m/s = 16.025m/s now from projectile's vertical motion we get h=ut+1/2*gt^2 45=16.025sin(20)t+.5*9.8*t^2 45 = 5.48t + 4.9t^2 solve t and get t=2.52 seconds use t with equation x=v.sin(theta)t =16.025cos(20)*2.52 =35.7641m so a)37.94m and b)2.52s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.