A car is moving on a curved section of highway at a tangential acceleration of .

Question

A car is moving on a curved section of highway at a tangential acceleration of .2t (m/s^2), t is in seconds (1) Write down the velocity and acceleration formulas (vectors) to describe the motion of the car by selecting an appropriate coordinate system. (2) If the initial speed is .2(m/s) at the initial instant t(initial)=0, what is the speed at the instant t=8 seconds that corresponds to point B in the plot? (3) The radii of gyration at point A (t(initial)=0) and point B (t=8) are 80 (m) and 100 (m), respectively. Determine the acceleration (vector) of the car at point B.

Explanation / Answer

1) VELOCITY OF THE CAR V = 1/2*t^2/2 + 1/2 ACCELARAION OF THE CAR A = 1/2t 2) VELOCITY OF THE CAR at T=8 secs = 0.2*64/2 + 0.2 = 6.6 m/s 3)ACCELARATION OF THE CAR AT point B, aCCELARATION = 5.6i + 14.2j m/s2

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