A car is moving with speed 19.7 m/s due south at one moment and 27.5 m/s due eas

ID: 1529700 • Letter: A

Question

A car is moving with speed 19.7 m/s due south at one moment and 27.5 m/s due east 6.00 s later.

Determine the magnitude and direction of its average velocity over this time interval.

Part B

Determine the magnitude and direction of its average acceleration over this time interval.

Part C

What is its average speed over this time interval?

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a). 32.4 m/s, 56.8 north of east b). 22.8 m/s, 33.2 north of east c). 45.5 m/s, 45.0 north of east d). The average velocity cannot be determined.

(a) Because we do not know the displacement over the given time interval, the average velocity is unknown.

(b) The average acceleration is

aav = Dv/Dt =[(27.5m/s)i -(-19.7m/s)j]/(6.00s) = (4.58m/s2)i + (3.28m/s2)j

the magnitude is | aav | = [(4.58m/s2)2 + (3.28m/s2)2]1/2 = 5.63 m/s2

We find the direction from tan q = (3.28m/s2)/(4.58m/s2) = 0.716, which gives q = 35.6° north of east.

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