The volume change on mixing for the liquid methyl formate (1) and liquid ethanol

Question

The volume change on mixing for the liquid methyl formate (1) and liquid ethanol (2) system at 298.15K
may be approximately represented by:
?Vmix = 0.8 x1 x2 cm3/mol
(a) Using this correlation, and the data V1= 67.28 cm3/mol, V2= 58.68 cm3/mol, determine the molar
volume of mixtures at x1 = 0, 0.2, 0.4, 0.6, 0.8, 1.0 in cm3/mol
(b) Analytically differentiate the above expression and show that
?V1E(partial) = 0.8 (x2)^2 and ?V2E(partial) = 0.8 (x1)^2 cm3/mol
And plot these partial molar excess volumes as a function of x1

Explanation / Answer

For part (a) Ve=delta Vmix, Ve=V-(x1V1+x2V2) you looking for V at each of the compositions.

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