The voltage across the 30-k? resistor in the figure (Figure 1) is measured with

Question

The voltage across the 30-k? resistor in the figure (Figure 1) is measured with (a) a 90-k? voltmeter, (b) a 500-k? voltmeter, and (c) a digital meter with 50-M?resistance. To two significant figures, what does each read?

Part A Constants Periodic Table Express your answer using two significant figures The voltage across the 30-kS2 resistor in the figure (Figure 1) is measured with (a) a 90-kf2 voltmeter, (b) a 500-k? voltmeter and (c) a digital meter with 50-M? resistance. To two significant figures, what does each read? Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B Express your answer using two significant figures gure 1 of 1> Submit Request Answer 30 k2 Part C 100 V-, 40 k ? 40 k? Express your answer using two significant figures

Explanation / Answer

a) when 90 k ohm voltemter is used

equivalent resistance of the ckt,

Req = 30*90/(30 + 90) + 40*40/(40 + 40)

= 42.5 k ohm

voltage across 30k read by voltmeter = 30*90/(30 + 90)*V/Req

= 30*90/(30 + 90)*100/42.5

= 52.9 V

b)

when 500 k ohm voltemter is used

equivalent resistance of the ckt,

Req = 30*500/(30 + 500) + 40*40/(40 + 40)

= 48.3 k ohm

voltage across 30k read by voltmeter = 30*500/(30 + 500)*V/Req

= 30*500/(30 + 500)*100/48.3

= 58.6 V

c)
when 50 M ohm voltemter is used

equivalent resistance of the ckt,

Req = 30*50*10^6/(30 + 50*10^6) + 40*40/(40 + 40)

= 49.9999 k ohm

voltage across 30k read by voltmeter = 30*50*10^6/(30 + 50*10^6)*V/Req

= 30*50*10^6/(30 + 50*10^6)*100/49.999

= 60.00 V

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