The voltage across an air-filled parallel-plate capacitor is measured to be V 1

Question

The voltage across an air-filled parallel-plate capacitor is measured to be V1 =94.0 V. When a dielectric is inserted and completely fills the space between the plates, as in the figure below, the voltage drops to V2 =27.6 V.

(a) What is the dielectric constant of the inserted material?


Can you identify the dielectric?

(b) If the dielectric doesn't completely fill the space between the plates, what could you conclude about the voltage across the plates?

The voltage across an air-filled parallel-plate capacitor is measured to be V1 =94.0 V. When a dielectric is inserted and completely fills the space between the plates, as in the figure below, the voltage drops to V2 =27.6 V. Correct: Your answer is correct. (b) If the dielectric doesn't completely fill the space between the plates, what could you conclude about the voltage across the plates? 16-p-049-alt.gif (a) What is the dielectric constant of the inserted material? Can you identify the dielectric? nylonbakelite paperneoprene rubberteflon

Explanation / Answer

Solution:

a) V1= 94 volts

V2 = 27.6 volts

C2=kC1 where k = dielectric constant

C=Q/V

since charge is constant , Q/V2= kQ/V1

1/V2= k 1/V1

k = V1/V2 = 94 / 27.6 = 3.4

dielectric constant of the inserted material = k = 3.4

The dielectric material is Nylon

b) If the dielectric does not completely fill it , V2 would be higher than the specified value. i.e. voltage is not at the minimal value.

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