- A CMOS clocked SR flip-flop uses a technology with unCox = 100 uA/V^2, upCox =
ID: 1935362 • Letter: #
Question
- A CMOS clocked SR flip-flop uses a technology with unCox = 100 uA/V^2, upCox = 25 uA/V^2, VDD = 2.5V, Vtn = -Vtp = 0.5V and the total capacitance at the output nodes equals 15fF. The inverter threshold voltage VM = 2.5V. The latch NMOS transistors Q1 and Q3 have (W/L)n = 1 um/0.5 um and the PMOS transistors Q2 and Q4 have (W/L)p = 2 um/0.5 um. 1. sketch the circuit showing SET, RESET, clock input and Q and Q' outputs. 2. propose for your design values of W/L of the SET and clock NMOS transistors and determine the associated SET time. Be aware that SET time will depend on your design and hence the optimum design is better rewarded.Explanation / Answer
The problem can be solved by using a 4 phase clock. The idea is to sample the previous stage only after its evaluation is complete. In phase 1, node P is pre-charged. In phase 2, P as well as the output are pre- charged. In phase 3, The gate evaluates. In phases 4 and 1, the output is isolated from the driver and remains valid. This is called a type 3 gate. It evaluates in phase 3 and is valid in phases 4 and 1. Similarly, we can have type 4, type 1 and type 2 gates. A type 3 gate can drive a type 4 or a type 1 gate. Similarly, type Type 1 Type 2 Type 4 Type 3 Drive Sequences Figure 3.14: CMOS 4 phase dynamic logic drive constraints 4 will drive types 1 and 2; type 1 will drive types 2 and 3; and type 2 will drive 32 types 3 and 4. We can use a 2 phase clock if we stick to type 1 and type 3 gates (or type 2 and type 4 gates) as these can drive each other. 3.4.3 Domino Logic P A B C Ck
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.