,Magnetism- please help with parts 1-5! A charged particle of mass m 7.3x10-8 kg
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,Magnetism- please help with parts 1-5!
A charged particle of mass m 7.3x10-8 kg, moving with constant velocity in the y- direction enters a region containing a constant magnetic field B 1.8T aligned with the positive z-axis as shown. The particle enters the region at (x,y)-(0.5 m, 0) and leaves the region at (x,y) -0, 0.5 m a time t-461 us after it entered the region. 1) With what speed v did the particle enter the region containing the magnetic field? m/s Submit You currently have O submissions for this question. Only 10 submission are allowed You can make 10 more submissions for this question 2) What is Fx, the x-component of the force on the particle at a time t 153.7 us after it entered the region containing the magnetic field. N Submit You currently have O submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question 3) What is Fy, the y-component of the force on the particle at a time t 153.7 us after it entered the region containing the magnetic field. NI SubmitExplanation / Answer
Part 1) v = d / T
Distance, d = 2pi R / 4 = 2 x pi x 0.5 /4 = 0.785 m
Time, T = 461 x 10^-6 sec
v = d / T = 1702.82 m/s (Ans)
Part 4) Magnetic force, F = (qVB) = mv^2 /r
q x 1702.82 x 1.8 = 7.3 x 10^-8 x 1702.82^2 / 0.5
q = 1.38 x 10^-4 C
and its negative charge because force is directd towards -ve x-axis
so q = - 8.97 x 10^-5 C (Ans)
2) F = mv^2 /r = 7.3 x 10^-8 x 1702.82^2 / 0.5 = 0.423 N
it travels pi/2 rad in 461 us
theta in 153.7 us = (pi /2)*153.7 / 461 = 0.524 rad = 30 degrees
Fx = - 0.423 cos30 = - 0.366 N (Ans)
3) Fy = 0.423 sin30 = - 0.2115 N (Ans)
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