, s 75 iNARIES OF THE U VOur Shopping Cart. The 1 PRINTER VERSION 4 BACK Chapter

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, s 75 iNARIES OF THE U VOur Shopping Cart. The 1 PRINTER VERSION 4 BACK Chapter 25, Problem 09 In an experiment designed to measure the speed of light, a laser is aimed at ? mirror that is 46.0 krn due north. A detector s placed 148 m due east of the laser. The mirror is to be aligned so that light from the laser refelects into the detector (a) When properly aligned, what angle should the normal to the surface of the mirror make with due south? (b) Suppose the mirror is misaligned, so that the actual angle between the normal to the surface and due south is too large by 0,0050, By how many meters (due east) will the reflected ray miss the detectori Mirror Laser Detector (a) Number (b) Number Click if you would like to Show Work for this question: Units Units Wo Question Attempts: O of 5 used SAVE FOR LATER BMIT ANSWER

Explanation / Answer

let ? be the angle between the incident and refllected rays

tan ? = 148/46000

=> ? = arctan(148/46000) = 0.18434o

since incident angle = reflected angle and

incident angle + reflected angle = ?

the asked angle = angle of incidence ,? = ?/2 = 0.09217o

b)

now incident angle, ? = 0.09217 + 0.0050 = 0.09717o

therefore ? = 2*? = 0.19434o

let the new detector position be x meter due east from source

tan?' = x/46000 m

                                   x = (46000 m)(tan0.19434o)

                                      = 156.02 m

therefore shift in detector positon = x - 148 = 8.02 m away from source due east

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