Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

, sapling Icarring CHEM 152, Universityof Arizona CHEM © Homel Chogg.com i www.s

ID: 570193 • Letter: #

Question

, sapling Icarring CHEM 152, Universityof Arizona CHEM © Homel Chogg.com i www.saplinglearning.co .php?id=481 6853 110% asearch Sapling Learning macmilan learning Jump to... View Profile Logout D 2/23/2018 11:55 PM 0662/1002/23/201 8 04:35 PM Print Calcuialor-Perodic Table Attempts Score Gradebook Assignment Ir Astion 13 at 20 Available From: 2/15/2018 06:00 PM Due Date: Points Possible: 100 Grade Categor: Homework 2/23/2018 11:55 PM a Sapling Learning A particular reactant decomoses with a half-life of 143 s when its initial cocentration is 0.332 M The same reactant decomposes with half-life of 241 s when its initial concentration is O. 197 M. Determine the reaction order You can check your answers You can view solutions after you complete the assignment. You have three attempts per question. You lose 10% of the points available to each answer in your question for each incorrect attermpt at that answer What is the value and unit of the rate constant for this reaction? 100 Number 10 Stiect answr DeTextbook O Help With This Topic 12 13 O Web Help & Videos 14 D Technical Support and Bug Reports 15 Pravkus Chek Answer Next Fxit omibiscmsuserview.phpid-1905274&ccurse-74696; ENG 1CS7 PM ^49) US 2/23/2018

Explanation / Answer

half life increases as we decrease initial concentration

hence its 2nd order , we can check it by 2nd order half life formula

t1/2 = 1 /k{Ao] where [Ao] = initial amount ,  

k = ( 1/ [Ao] t1/2) = ( 1/ 0.332 x 143) = 0.021 M-1s-1

k = [ 1/( 0.197 x 241) ] = 0.021 M-1s-1

hence rate constant is same at both situations. hence 2nd order kinectis obeyed

Hence order is 2

rate constant k = 0.021 M-1 s-1