A circular coil enclosing an area of 102 cm2 is made of 201 turns of copper wire

Question

A circular coil enclosing an area of 102 cm2 is made of 201 turns of copper wire. The wire making up the coil has resistance of 2.0 , and the ends of the wire are connected to form a closed circuit. Initially, a 1.4 T uniform magnetic field points perpendicularly upward through the plane of the coil. The direction of the field then reverses so that the final magnetic field has a magnitude of 1.4 T and points downward through the coil. If the time required for the field to reverse directions is 0.19 s, what average current flows through the coil during that time?

Explanation / Answer

We generally do not answer the questions of those who are having low rating. You are having a rating of "56%". Please rate all answers and improve your rating. Even if you find the answers are incorrect, first rate Lifesaver or helpful to the best answer and then rate other answers as not helpful. But do rate them for the good of both of us. Thanks!! Coming to the problem Faraday's Law: E = N * d(BA)/dt =>E = (201)*102*(10^(-4))*(1.4-(-1.4))*(1/0.19) =>E = 30.213 V So I = E/R = 30.213/2 = 15.107 Amperes.

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