A tennis player swings her 1000 g racket with a speed of 9 m/s. She hits a 60 g

Question

A tennis player swings her 1000 g racket with a speed of9m/s. She hits a 60 g tennis ball that was approaching her at a speed of20m/s. The ball rebounds at42m/s. (a) What is the magnitude of the change in momentum of the tennis ball? (Remember that momentum is a vector quantity.)
kg m/s

(b) How fast is her racket moving immediately after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision.
HINT: Think about Newton's Third Law for the ball and the racquet.
m/s

(c) If the tennis ball and racket are in contact for 10 ms, what is the average force that the racket exerts on the ball? HINT: Remember that we can approximate the Impulse as the product of some average force times the time duration of the collision.
N
(a) What is the magnitude of the change in momentum of the tennis ball? (Remember that momentum is a vector quantity.)
kg m/s

(b) How fast is her racket moving immediately after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision.
HINT: Think about Newton's Third Law for the ball and the racquet.
m/s

(c) If the tennis ball and racket are in contact for 10 ms, what is the average force that the racket exerts on the ball? HINT: Remember that we can approximate the Impulse as the product of some average force times the time duration of the collision.
N

Explanation / Answer

CHANGE IN MOMENTUM OF BALL=.06*(20-(-42))=.06*62=3.72KGm/s 1000*9-60*20=60*42+1000*v (9000-1200-2520)/1000=v v=5.28m/s change in momentum=3.72=F*10*10^-3 F=372 N

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