A tennis player swings her 1000 g racket with a speed of 9.00m/s . She hits a 60

Question

A tennis player swings her 1000 g racket with a speed of 9.00m/s . She hits a 60 g tennis ball that was approaching her at a speed of 14.0m/s . The ball rebounds at 45.0m/s . A.) How fast is her racket moving immediately after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision. B.) If the tennis ball and racket are in contact for 5.00 ms, what is the average force that the racket exerts on the ball?

Explanation / Answer

conservation of momentum take hitting direction as positive m1v1+m2u1=m1v2+m2u2 1000*9-60*14=45*60+1000*x x=5.46 m/sec b)Ft=change in momentum==>F=m(v2-v1)/t=60*(45+14)*10^3/5*10^-3=708N

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