A tennis player swings her 1000 g racket with a speedof 11 m/s. She hits a 60 gt

Question

A tennis player swings her 1000 g racket with a speedof 11 m/s. She hits a 60 gtennis ball that was approaching her at a speedof 17 m/s. The ball reboundsat 36m/s. (a) How fast is her racket moving immediately after the impact? Youcan ignore the interaction of the racket with her hand for thebrief duration of the collision.
m/s

(b) If the tennis ball and racket are in contact for 10 ms, what isthe average force that the racket exerts on the ball?
N

(c) How does this compare to the ball's weight?
Favg / Wball =
(a) How fast is her racket moving immediately after the impact? Youcan ignore the interaction of the racket with her hand for thebrief duration of the collision.
m/s

(b) If the tennis ball and racket are in contact for 10 ms, what isthe average force that the racket exerts on the ball?
N

(c) How does this compare to the ball's weight?
Favg / Wball =

Explanation / Answer

   (1/2)m1u12+(1/2)m2u22=(1/2)m1v12+(1/2)m2v22  
And
     m1u1+m2u2 =m1v1+m2v2   
Solving for the final speeds
  Speed of the racket after collision is
   v1 = [(m1 -m2) / (m1+m2) ]u1 + [ 2m2 /(m1+m2)]u2   
   here m1 = 1000g ,m2 = 60g , u1 = 11m/s , u2 =-17m/s
   plug in values.
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The average force that the racket exerts on the ballis
   F = m2 (v2 - u2 ) / t
   Here v2 = 36m/s and t =10x10-3 s .
plug in values
note: make sure both speeds add up as the other isnegative.
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   ratio of force to weight
     Favg / Wball = answer to part b / m2g
   g = 9.8 m/s^2   plug in values         

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