A conducting rod of length L slides freely down an inclined plane, as shown in t

Question

A conducting rod of length L slides freely down an inclined plane, as shown in the figure. The plane is inclined at an angle ? from the horizontal. A uniform magnetic field of strength B acts in the positive y-direction. Determine the magnitude and the direction of the current that would have to be passed through the rod to hold it in position on the inclined plane. (Use any variable or symbol stated above along with the following as necessary: g. Indicate your direction based on the side view.) magnitude i = 1 direction

Explanation / Answer

Balancing magnetic force and gravitational force,we have

iLB = mgsin

I = (mgsin)/(LB) A

By right hand rule:

Direction wil be = Above the page [according to side view ]

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