A car is traveling at 47.0 km/h on a flat highway. e coefficient of friction bet

Question

A car is traveling at 47.0 km/h on a flat highway. e coefficient of friction between road and tires on a rainy day is 0.100, what is the minimum distance in which the 98.6 Your response differs from the correct answer by more than 10%. Double check your calculations. m (b) Wha 16.6 Your response differs from the correct answer by more than 10%. Double check your calculations. m at is the stopping distance when the surface is dry and the coefficient of friction is 0.600 Need Help? Talk to a Tutor

Explanation / Answer

(a) By using equation of motion,

v^2 = u^2 + 2as

Where, v is final velocity = 0

u is initial velocity = 47 km/hr = 13.06 m/s

a is acceleration

s is stopping distance

Now, for acceleration

F = Ff

ma = umg

a = ug = 0.1*9.8 = 0.98 m/s

Acceleration will be negative since, it opposes the motion

0 = 13.06^2 - 2*0.98*s

s = 87.02 m

(b) Here, F = Ff

ma = umg

a = ug = 0.6*9.8 = 5.88 m/s

v^2 = u^2 + 2as

0 = 13.06^2 - 2*5.88*s

s = 13.06^2 /(2*5.88)

= 14.50 m

Answer

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