A freezer has a coefficient of performance of 6.30. It is advertised as using 39

Question

A freezer has a coefficient of performance of 6.30. It is advertised as using 396 kWh/yr. Note: One kllowatt-hour (kWh) is an amount of energy equal to running a 1-kw appliance for one hour. (a) On average, how much energy does it use in a single day? (b) On average, how much energy does it remove from the refrigerator in a single day? (c) what maximum mass of water at 21.1°C could the freezer freeze in a single day? (The latent heat of fusion of water is 3.33 × 105 l/kg, and its specific heat is 4186 l/kg·°C.) kg Need Help? Readt Save ProgressPractice Another Version nother Version

Explanation / Answer

Solution)

A) Energy used in single day=( 396 kWh/yr)/365=1.08kWH *(36*10^5)=3.8*10^6 J (Ans)

B) Energy Removed=1.08*6.30=6.83 kW*(36*10^5) =24.5 *10^6 J (Ans)

C) Q = m(4186)(21.1) + m(3.33E5)

= m(8.8E4) + m(33.3E4)

= m(42.1*10^4)
m = (24.5*10^6)/(42.1*10^4)

Mass, m=58.19 kg (Ans)

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