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ExperimentsTand 2:0 hrn\'s Law and DCind ACElectriccircuits Fig. 4 shows two res

ID: 1881821 • Letter: E

Question

ExperimentsTand 2:0 hrn's Law and DCind ACElectriccircuits Fig. 4 shows two resistors R, and R, connected in parallel. The conductances (1/R) of resistors in parallel add. i.e., R23 R2 R3 23 = (R2+R3) Fig. 4 also shows the parallel combination of R, and R, connected in series with R,. The total resistance R in the circuit is R,+ Ry. The total current through the circuit is I, R (RI +R 23) At branch point (b), the current 1I, flowing through R, divides into currents I, through R, and I, through R I1 -12+13 (current addition) Equation (I) also holds at branch point (c), where I2 and I, are the currents flowing into (c) and I, is the current leaving (c). Since the same voltage V23 is across both R2 and R v23 = 12R2 13R3 and 13-R2 12 R3 ion) Parallel resistors are useful as current dividers. Circuit Diagram Sketch R, AM VM HVM Fig. 4

Explanation / Answer

Ans 1. The slope of I-V curve represents 1/R value of resistance

Ans4. The series connection has the same current but different potential drop across the resistors.

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