A 75.0-kg ice skater moving at 11.6 m/s crashes into a stationary skater of equa

Question

A 75.0-kg ice skater moving at 11.6 m/s crashes into a stationary skater of equal mass. After the collision, the two skaters move as a unit at 5.80 m/s. Suppose the average force a skater can experience without breaking a bone is 4,235 N. If the impact time is 0.113 s, does a bone break? At Yes Since P = mv, can substitute mv for p No At The force without breaking a bone is 4,235 N The force from the collusion is 3,849.56 N F (75.0 kg) (5.80 m/s) 0.113 s A bone will not break F 435 kg*m/s 0.113 s F = 3,849.56 N

Explanation / Answer

for the moving skater

initial momentum Pi = m*vi

final momentum Pf = m*vf

change in momentum dP = Pf - Pi

dP = m*vf - m*vi = m*(vf - vi)

force experienced F =dP/dt

F = m*(vf - vi)/t

F = 75*(5.8 - 11.6)/0.113

F = 3849.56 N

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for the skater at rest

initial momentum Pi = m*vi = 0

final momentum Pf = m*vf

change in momentum dP = Pf - Pi

dP = m*vf - m*vi

force experienced F =dP/dt

F = m*(vf - vi)/t

F = 75*(5.8 - 0)/0.113

F = 3849.56 N

the force experienced is 3849.56 < 4235

the bone does not break

NO

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