labb female aaBB female D Question 4 1 pts A fruitfly is found to have the genot

Question

labb female aaBB female D Question 4 1 pts A fruitfly is found to have the genotype AaBbCc. How many different gamete genotypes could this fly produce? 8 32 16 DQuestion 5 2 pts In peas, Round seeds are dominant over Wrinkled, and Yellow is dominant over Green. A wrinkled, yellow (aaBb) plant is crossed with a round, yellowlAaBb) plant and a large number of offspring are produced. Given the results below, calculate the overal Chi-Squared (observed) value for these data. Hint: You will first need to determine the expected Phenotypic ratio for this cross.

Explanation / Answer

4) The correct option is 8.

When genotype of fruitfly is AaBbCc, then it produces eight potential gamete types - ABC, ABc, AbC, aBC, Abc, aBc, abC and abc. The chance of any of these being in any given egg or sperm cell is exactly same.

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