l\'total((di)/(dt)) = L1*((di)/(dt))+L2*((di)/(dt))+L3*((di)/(dt))+...etc but I\

Question

l'total((di)/(dt)) = L1*((di)/(dt))+L2*((di)/(dt))+L3*((di)/(dt))+...etc   but I'm not getting it. HELP!

i think part C is 17.2 mH.

1. Inductor Combinations and an RMS softball Mathematically prove that: (a) inductors in series add up like resistors, so that series L1 L2 La LA t if we ignore any mutual inductance (i.e., interaction between the inductors), and... (b) inductors in parallel add up like resistors, so that parallel if we ignore any mutual inductance between the individual inductors Cc) Calculate the equivalent inductance of the circuit below: L2 40 mH LA 20mH L6 40 mH A O- L1 L3 L5 L7 EQ 500mH 20mH 30mH 100 mH BO

Explanation / Answer

As same current flows throughout the components connected in series, di/dt part will get cancelled out and inductors in series will be total sum just like in case of resistance

Similarly in a parallel combination, voltage difference is same,so is the Ldi/dt part

So, di1/dt=E/L1

Similarlly for other currents

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