4. A conveyor belt feeds 10 canned beverages per second up an incline. The total

Question

4. A conveyor belt feeds 10 canned beverages per second up an incline. The total change in height is 6 m from beginning to end. Ignoring nonconservative forces and assuming the velocity is constant, what is the minimum amount of power needed for this conveyor belt (in kW)? 4. A conveyor belt feeds 10 canned beverages per second up an incline. The total change in height is 6 m from beginning to end. Ignoring nonconservative forces and assuming the velocity is constant, what is the minimum amount of power needed for this conveyor belt (in kW)?

Explanation / Answer

Mass of can is missing from question

Power will be equal to change in potential energy per second.

power= mgh =[10*(mass of 1 can) *9.81 *6] KW

By putting value of mass above, you will get an answer.

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