Based on the estimated power demand for the rest stop (216.676 kWh required per

Question

Based on the estimated power demand for the rest stop (216.676 kWh required per day), the assumption of 15% efficiency for solar panels, and the solar irradiance data provided below, determine the total surface area of solar panels required for the highway rest stop.

Time Irradiance (W/m^2)
7am 0.0
8am 14.6
9am 86.1
10am 137.1
11am 182.7
12pm 201.1
1pm 255.9
2pm 293.7
3pm 302.7
4pm 203.7
5pm 0.0

Total surface area of solar panels required (m^2): _______________________

Assuming $375 per m^2, total cost of solar panels: ______________________

Explanation / Answer

You have 0%respect score. I hope you will rate the answer. ----------------------------------------------------------------------------------- total duration of radiance = 7am to 5 pm = 9 hours Let surface area of the panel = A Total energy collected during the day = (0+14.6+86.1+137.1+182.7+201.1+255.9+293.7+302.7+203.7+ 0) *A *9 energy =1677.6*9*A = 15098.4 A=15.098*A KWh Required = 216.676 = 15.098*A So Area of panel is = 216.676/15.098 = 14.3513 m^2 Cost per m^2 of panel = $375 Total cost = $ 375 * 14.3513 = $5381.7375

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