4. A rifle bullet of mass \"mi strikes a block of10 that rests on a frictionless

Question

4. A rifle bullet of mass "mi strikes a block of10 that rests on a frictionless horizontal state The bullet exits the other end of the block at a speed of 4 of its incoming speed. The block the moves along the frictionless surface before encountering a spring where it compresses the spring anti- distance "s". The spring constant is "r. a. Write out the momentum equation for the collision. Given m, k, s] determines a. The blocks velocity just after the collision. b. The initial speed of the bullet in IOM O in ns Fine

Explanation / Answer

a)

momentum before collision = momentum after collision

m*v = 10m*u + mv/4

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part (a)

total kinetic energy of the block after collisio = potential energy stored in spring

(1/2)*10m*u^2 = (1/2)*k*s^2

u = s*sqrt(k/10m) <<<------ANSWER

(b)

from momentum equation

m*v = 10m*u + m*v/4

10u = 3v/4

v = (40/3)*u

v = (40/3)*s*sqrt(k/10m)

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