4. A proton is moving to the right with a velocity of 2 x 106 m/s in a magnetic

Question

4. A proton is moving to the right with a velocity of 2 x 106 m/s in a magnetic field of strength 2 T pointing out of the page. a) Find the magnitude and the direction of the force acting on the proton b) If we let the proton continue, it will move in a circle What is the radius of the circle? c) If we instead want the proton to move in a straight line, we can apply a electic field to counteract the effect of the magnetic field. What are the magnitude and direction of this electric field? B-2T profon char . x101 c

Explanation / Answer

(1)

F = q (VXB) = qvB sin theta = 1.6 * 10^-19 ( 2* 10^6) ( 2T) sin 90 = 6.4 * 10^-13 N

F= q ( iXk) = -j ( downward direction)

(2)

r= mv/ qB

= (1.67 * 10^-27 ( 2* 10^6)/ 1.6* 10^-19 ( 2)

= 0.0104 m

(c)

Eq = Bqv

E/B = v

E = Bv = 2T ( 2 * 10^6) = 4* 10^6 V/m

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