Your Tea A 1 450 N uni boom at -56.0. to the vertical is supported by a cable at

Question

Your Tea A 1 450 N uni boom at -56.0. to the vertical is supported by a cable at an angle bottom, and an object of weight m- 2 375 N hangs from its top -34 ge to the horizontal as shown In the gure below the boom ts pivoted at the (a) Find the tension in the support cable. 1454 Your response differs from the correct answer by more than 10%. Double check your calculations, kN (b) Find the components of the reaction force exerted by the foor on the boom horizontal component magnitude KN direction D KN vertical component magnitude direction downward D×

Explanation / Answer

a] Balancing torque about hinge, T sin ( 180 -56 -34 degree) *3/4 L = mg sin (90-56 degree) *L/2 +  W sin (90-56 degree) *L

T = (2375* sin 34 degree + 1450*sin 34 degree *0.5)4/3= 2311N

= 2.311 kN answer

b] Horizontaal force by tension is at left, so force at floor be towards right.

magnitude = T cos 34 degree = 2.311 cos 34 degree = 1.916 kN

vertical component magnitude = 2.375+1.450 -2.311 sin 34 degree = 2.533 kN

direction = upward in order to balance the weight.

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