12 -2 points SerPSET9 31 P045 Notes Ask Your In a 240 tum automobile alternator,
ID: 1774476 • Letter: 1
Question
12 -2 points SerPSET9 31 P045 Notes Ask Your In a 240 tum automobile alternator, the magnetic flux in each turn is 's-2.50 x 104 cos a t, where is in webers, a, is the angular speed of the aterr ator, and t is in seconds. The alternator is geared to rotate two times for each engine revolution. The engine is running at an angular speed of 1.00 x 103 rev/min (a) Determine the induced emf in the alternator as a function of time. (Assume is in V. (b) Determine the maximum emf in the alternator Need Help? EithExplanation / Answer
total magnetic flux = N*phi
emf = -rate of change in flux
emf = -d(phi)/dt
emf = -2*N*2.5*10^-4*cos(wt)*w
emf = 2*N*w*2.5*10^-4*sin(wt)
w = 10^3rev/min = 10^3*2pi/60 rad/s = 104.7 rad/s
emf = 2*240*104.7*sin(wt)
emf = 50256*sin(wt)
=====================
emf = emax*sin(wt)
maximum emf = 50256 V <<<-----ANSWER
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.