A woman is riding a jetski at a speed of 28 m/s and notices aseawall straight ah

Question

A woman is riding a jetski at a speed of 28 m/s and notices aseawall straight ahead. The farthest she can lean the craft inorder to make a turn is 19°. This situation is like that of acar on a curve that is banked at an angle of 19°. If she triesto make the turn without slowing down, what is the minimum distancefrom the seawall that she can begin making her turn?

A woman is riding a jetski at a speed of 28 m/s and notices aseawall straight ahead. The farthest she can lean the craft inorder to make a turn is 19°. This situation is like that of acar on a curve that is banked at an angle of 19°. If she triesto make the turn without slowing down, what is the minimum distancefrom the seawall that she can begin making her turn?

Explanation / Answer

Applying Newton's second law along the radius and first lawin the vertical direction is                               Nsin = mv2 / r and                       N cos = mg               r = v2/ g*tan                                      = 28*28 / 9.8*tan19                                 = 232.55 m the minimum distance from the seawall that she can begin making herturn is 232.55 m.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.