A rock climber throws a small first aid kit to another climber whois higher up t

Question

A rock climber throws a small first aid kit to another climber whois higher up the mountain. The initial velocity of the kit is 8.09m/s at an angle of 48.3 ° above the horizontal. At the instantwhen the kit is caught, it is traveling horizontally, so itsvertical speed is zero. What is the vertical height between the twoclimbers?

I tried using the kinematics equation and I know that the verticaldistance is represented by "y", the Ax is 0 and the VoX is 8.09m/s.I set up my right triangle but I was confused as to if I shouldfind t or not?

Explanation / Answer

I think you can just go ahead and use V2=Vo2+ 2a(y-yo) Set you lower climber at 0, so yo=o. That shoulddetermine your height. acceleration= gravity= -9.80m/s2V=0 I hope this helps

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