A moving particle encounters an external electric field thatdecreases its kineti

Question

A moving particle encounters an external electric field thatdecreases its kinetic energy from 9520 eV to 7060 eV as theparticle moves from position A to position B The electric potential at A is -55.0 V and the electricpotential at B is +27.0 V determine the charge of the particle Include the algebraic sign + or - with your answer The electric potential at A is -55.0 V and the electricpotential at B is +27.0 V determine the charge of the particle Include the algebraic sign + or - with your answer

Explanation / Answer

          The work done = change in kinetic energy               q*V = change in kinetic energy                q*(Vb- Va) = K2-K1                           q = ( K2 - K1 ) / (Vb-Va)                                =(7060 - 9520)*1.602*10-19 J / (27.0V + 55.0V)                                =---------- C              

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