A moving particle encounters an external electric field thatdecreases its kineti

Question

A moving particle encounters an external electric field thatdecreases its kinetic energy from 9520 eV to 7060 eV as theparticle moves from position A to position B . The electricpotential at A is -55.0 V, and the electric potential at B is +27.0 V .Determine the charge of the particle . Include the algebraic sign (+ or - ) with your answer . A moving particle encounters an external electric field thatdecreases its kinetic energy from 9520 eV to 7060 eV as theparticle moves from position A to position B . The electricpotential at A is -55.0 V, and the electric potential at B is +27.0 V .Determine the charge of the particle . Include the algebraic sign (+ or - ) with your answer .

Explanation / Answer

A moving particle encounters an external electric field thatdecreases its kinetic energy from 9520 eV to 7060 eV as theparticle moves from position A to position B . The electricpotential at A is -55.0 V, and the electric potential at B is +27.0 V .Determine the charge of the particle . Include the algebraic sign (+ or - ) with your answer .
the charged particle while moving through points A to B
change in kinetic energy=potential difference*charge
so charge=change in kinetic energy/potential difference
             =[9520-7060]ev/[27-(-55)]=30*1.6*10-19C
the charge is positive.

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