A swimmer maintains a speed of .15 m/s relative to the waterwhen he swims direct

Question

A swimmer maintains a speed of .15 m/s relative to the waterwhen he swims directly toward the opposite shore of a river. Theriver has a current that flows at .75 m/s. a) how far downstream is he carried in 1.5 minutes? b) what is his velocity relative to an observer on shore? A swimmer maintains a speed of .15 m/s relative to the waterwhen he swims directly toward the opposite shore of a river. Theriver has a current that flows at .75 m/s. a) how far downstream is he carried in 1.5 minutes? b) what is his velocity relative to an observer on shore?

Explanation / Answer

Given : Speed of swimmer ( v1 ) = 0.15 m/s river speed ( v2 ) = 0.75 m/s time ( t ) = 1.5 min The relative speed ( v ) = v1 + v2 = 0.15 + 0.75 = 0.9m/s distance = velodity * timea).               = 0.9 m * 90 s = ---- m Solve it I hope it helps you

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