A single circular loop of wire of radius 0.75 m carries aconstant current of 3.0
ID: 1753728 • Letter: A
Question
A single circular loop of wire of radius 0.75 m carries aconstant current of 3.0 A. The loop may be rotated about an axisthat passes through the center and lies in the plane of the loop.When the orientation of the normal to the loop with respect to thedirection of the magnetic field is 25°, the torque on the coilis 1.8 N•m. What is the magnitude of the uniform magneticfield exerting this torque on the loop?a. 0.46 T
b. 0.37 T
c. 3.0 T
d. 1.7 T
e. 0.80 T A single circular loop of wire of radius 0.75 m carries aconstant current of 3.0 A. The loop may be rotated about an axisthat passes through the center and lies in the plane of the loop.When the orientation of the normal to the loop with respect to thedirection of the magnetic field is 25°, the torque on the coilis 1.8 N•m. What is the magnitude of the uniform magneticfield exerting this torque on the loop? 0.46 T 0.37 T 3.0 T 1.7 T 0.80 T
Explanation / Answer
Given that the radius of the loop is r = 0.75m Current is I = 3.0A angle is = 250 torque is = 1.8 N.m ------------------------------------------------------------- The torque onthe loop is = IAB sin B= / IAsin =(1.8 N.m) /(3.0A*r2*sin250) = (1.8 N.m) /(3.0A**(0.75m)2*sin250) =--------- T torque is = 1.8 N.m ------------------------------------------------------------- The torque onthe loop is = IAB sin B= / IAsin =(1.8 N.m) /(3.0A*r2*sin250) = (1.8 N.m) /(3.0A**(0.75m)2*sin250) =--------- TRelated Questions
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