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Two capacitors C1= 25.0 x 10 -6 F and C2 = 5.00 x10 .6 F are conneted in paralle

ID: 1749331 • Letter: T

Question

Two capacitors C1= 25.0 x 10-6 F and C2 = 5.00 x10.6 F are conneted in parallel and charged with a 100-Vpower supply. a.) Calculate the total energy stored in the twocapacitors. b.) What potential difference would be required across thesame two capacitors connected in series in order that thecombination store the same energy as in (a)? Two capacitors C1= 25.0 x 10-6 F and C2 = 5.00 x10.6 F are conneted in parallel and charged with a 100-Vpower supply. a.) Calculate the total energy stored in the twocapacitors. b.) What potential difference would be required across thesame two capacitors connected in series in order that thecombination store the same energy as in (a)?

Explanation / Answer


   C
1 = 25 µF    C2 = 5.0 µF    voltage (V) = 130 V (a)    a they are parallel the resultant capacitance(CRp) will be       CRp = C1 +C2    now the total energy stored (U) in twocapacitors will be    U = (1 / 2) (CRpV2)        = ...........J (b)    when the same capacitors are connected in seriesthen the resultant capacitance (CRs) will be    CRs = 1 / C1 + 1 /C2           =C1C2 / C1 + C2           =...........F    as the energy stored is same as U    U = (1 / 2)(CRsV2)        potential difference would be requiredacross the same two capacitors connected in series can    be evaluated from the aboveformula           =...........F    as the energy stored is same as U    U = (1 / 2)(CRsV2)        potential difference would be requiredacross the same two capacitors connected in series can    be evaluated from the aboveformula
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