A circular-motion addict of mass 90 kgrides a Ferris wheel around in a vertical

Question

A circular-motion addict of mass 90 kgrides a Ferris wheel around in a vertical circle of radius 10 m ata constant speed of 6.3 m/s. (a) What is the period of the motion s?
1

(b) What is the magnitude of the normal force on the addict fromthe seat when both go through the highest point of the circularpath N?

(c) What is it when both go through the lowest point N? (a) What is the period of the motion s?
1

(b) What is the magnitude of the normal force on the addict fromthe seat when both go through the highest point of the circularpath N?

(c) What is it when both go through the lowest point N?

Explanation / Answer

   Mass, M = 70 kg    Radius, R = 10 m       Linear Speed, V = 6 m/s    Angular speed, = V / R = 6 / 10 = 0.6rad / s     (a)    Time period, T = 2 /                           =2 * 3.14 / 0.6                          = 10.47 s (b)     Normal Force at the highest point , N = (MV2 / R ) - M g                                                              =( 70 * 36 / 10 ) - 70 * 9.8                                                              =252 - 686                                                             = -434 N (c)    normal force at the lowest point, N = (MV2 / R )  + M g                                                              =( 70 * 36 / 10 ) + 70 * 9.8                                                              =252 + 686                                                             = 938 N                                                              =( 70 * 36 / 10 ) + 70 * 9.8                                                              =252 + 686                                                             = 938 N

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