Figure 9-48 gives an overhead view of the path taken by a 0.165kg cue ball as it
ID: 1742563 • Letter: F
Question
Figure 9-48 gives an overhead view of the path taken by a 0.165kg cue ball as it bounces from a rail of a pool table. The ball'sinitial speed is 2.52 m/s, and the angle1 is 62.4°. The bounce reverses they component of the ball's velocity but does not alter thex component. What are (a) angle2 and (b) the magnitudeof the change in the ball's linear momentum? (The fact that theball rolls is irrelevant to the problem.)
Fig. 9-48
Problem 20.
(a)
Number
Units
Chapter 9, Problem 20Figure 9-48 gives an overhead view of the path taken by a 0.165kg cue ball as it bounces from a rail of a pool table. The ball'sinitial speed is 2.52 m/s, and the angle1 is 62.4°. The bounce reverses they component of the ball's velocity but does not alter thex component. What are (a) angle2 and (b) the magnitudeof the change in the ball's linear momentum? (The fact that theball rolls is irrelevant to the problem.)
Fig. 9-48
Problem 20.
(a)
Number
Units
This answer has no units° (degrees)mkgsm/sm/s^2NJWN/mkg·m/s or N·sN/m^2 or Pakg/m^3gm/s^3timesExplanation / Answer
Given that the initial speed is U = 2.52 m/s The angle is 1 = 62.40 mass of the ball is m = 0.165 kg ----------------------------------------------------------------- mass of the ball is m = 0.165 kg ----------------------------------------------------------------- since there is no external force in y-direction then momentum isconserved . m*Usin 1 = m*Usin 2 Then 1 = 2 = 62.40 changein moemntum is P = m*Ucos 2 (-j) - m*Ucos 2 (+j) =2 m*U cos 2 = ------- kg.m/s (j)Related Questions
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