A car is parked on a cliff overlooking the ocean on an incline thatmakes an angl

Question

A car is parked on a cliff overlooking the ocean on an incline thatmakes an angle of 17.0° below thehorizontal. The negligent driver leaves the car in neutral, and theemergency brakes are defective. The car rolls from rest down theincline with a constant acceleration of 2.75 m/s2 for a distance of60.0 m to the edge of the cliff, whichis 45.0 m above the ocean. (a) Find the car's position relative to thebase of the cliff when the car lands in the ocean.
1 m
(b) Find the length of time the car is in the air.
2 s (a) Find the car's position relative to thebase of the cliff when the car lands in the ocean.
1 m
(b) Find the length of time the car is in the air.
2 s

Explanation / Answer

Here the cars velocity at the edge as, v2-u2=2as v2-0=2*2.75*60 v=330 v=18.165m/s It goes with an angle =73 below the horizontal Its initial vertical velocity is vy=vsin73=18.165sin73=17.3721m/s Its velocity when it lands is v2-u2=2gh v2-17.37212=2*9.8*45 v=34.4m/s The time taken as, v=u+gt 34.4=17.3721+9.8t t=1.7375s The position of the car is x=vx*t=18.165cos73*1.7375=9.227961m This is the distance from the base as. Hence we get by it.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.