A simple pendulum consists of a 4.8 kg point mass hanging at the end of a 2.1 m

Question

A simple pendulum consists of a 4.8 kg point mass hanging at the end of a 2.1 m long light string that is connected to a pivot point. Calculate the magnitude of the torque (due to the force of gravity) around this pivot point when the string makes a 5.4? angle with the vertical. The acceleration of gravity is 9.81 m/s2 . Answer in units of N · m. A simple pendulum consists of a 4.8 kg point mass hanging at the end of a 2.1 m long light string that is connected to a pivot point. Calculate the magnitude of the torque (due to the force of gravity) around this pivot point when the string makes a 5.4? angle with the vertical. The acceleration of gravity is 9.81 m/s2 . Answer in units of N · m.

Explanation / Answer

Hi, Here the weight component of the mass perpenducular to thestring of the pendulum is mgcos =(4.8kg)(9.8m/s2)(cos5.4)                                                                                                                                       = 46.83N Then torque = (2.1m)(46.83N)                      = 98.343 M.m hope this helps you.

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